LINQ – Zwei Arrays vergleichen

Hier wollen wir zwei Array vergleichen, um die fehlende Array-Elemente herauszufinden. Beide Arrays sind vom Typ “Element” .

  public class Element
  {
    public int DeviceKey { get; set; }
    public int SwitchKey { get; set; }
  }

Das Array “fullElements” beinhaltet alle Kombinationen. Das “incompleteElements” hat nur einen Teil davon.

    public static void Main(string[] args)
    {
      var fullElements = new List<Element>();
      var incompleteElements = new List<Element>();

      // (Device = 1) Beide Arrays haben die gleichen Pärchen
      fullElements.Add(new Element{ DeviceKey = 1, SwitchKey = 1});
      incompleteElements.Add(new Element { DeviceKey = 1, SwitchKey = 1 });

      fullElements.Add(new Element { DeviceKey = 1, SwitchKey = 2 });
      incompleteElements.Add(new Element { DeviceKey = 1, SwitchKey = 2 });

      fullElements.Add(new Element { DeviceKey = 1, SwitchKey = 3 });
      incompleteElements.Add(new Element { DeviceKey = 1, SwitchKey = 3 });

      // (Device = 2) Nur ein Array hat elemente
      fullElements.Add(new Element { DeviceKey = 2, SwitchKey = 1 });
      fullElements.Add(new Element { DeviceKey = 2, SwitchKey = 9 });
      fullElements.Add(new Element { DeviceKey = 2, SwitchKey = 3 });

      // (Device = 3) Die Arrays haben gemischte Elemente
      fullElements.Add(new Element { DeviceKey = 3, SwitchKey = 1 });
      incompleteElements.Add(new Element { DeviceKey = 3, SwitchKey = 1 });

      fullElements.Add(new Element { DeviceKey = 3, SwitchKey = 2 });
      fullElements.Add(new Element { DeviceKey = 3, SwitchKey = 22 });
      incompleteElements.Add(new Element { DeviceKey = 3, SwitchKey = -1 });

      fullElements.Add(new Element { DeviceKey = 3, SwitchKey = 33 });
      incompleteElements.Add(new Element { DeviceKey = 3, SwitchKey = 33 });

      // TODO ...

      Console.ReadKey();
    }

Hier zwei Möglichkeiten, um die fehlende Elemente zu finden:

Lösung 1)

      // Solution 1)
      foreach (var fullElement in fullElements)
      {
        // Device found
        if (!incompleteElements.Any(incomplete => 
              incomplete.DeviceKey.Equals(fullElement.DeviceKey) && 
              incomplete.SwitchKey.Equals(fullElement.SwitchKey))
            )
        {
          Log("Device/Switch not found");
        }
      }

Lösung 2)

      // Solution 2)
      var notMappedElements = fullElements.FindAll(fullElement => 
        !incompleteElements.Any(incomplete =>
          incomplete.DeviceKey.Equals(fullElement.DeviceKey) && 
          incomplete.SwitchKey.Equals(fullElement.SwitchKey)));

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